1class Solution {2 public:3 bool evaluateTree(TreeNode *root) {4 return (root->val < 2) ? root->val5 : (root->val == 2) ? evaluateTree(root->left) || evaluateTree(root->right)6 : evaluateTree(root->left) && evaluateTree(root->right);7 }8};
WPM •0 •0
ACC •0 •0
TIME •0