Day of the Year LeetCode solution in Python

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class Solution:
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    def dayOfYear(self, date: str) -> int:
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        d = {
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            1: 31,
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            2: 28,
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            3: 31,
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            4: 30,
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            5: 31,
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            6: 30,
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            7: 31,
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            8: 31,
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            9: 30,
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            10: 31,
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            11: 30,
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            12: 31,
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        }
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        year = int(date[:4])
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        if year % 4 == 0:
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            if year % 100 == 0:
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                if year % 400 == 0:
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                    d[2] = 29
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            else:
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                d[2] = 29
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        month = int(date[5:7])
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        day = int(date[8:])
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        ans = 0
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        for i in range(1, month + 1):
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            ans += d[i]
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        return ans - (d[month] - day)