Day of the Week LeetCode solution in Python

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class Solution:
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    def dayOfTheWeek(self, day: int, month: int, year: int) -> str:
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        LOWEST_DAY, LOWEST_MONTH, LOWEST_YEAR, DAY = 1, 1, 1971, 5
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        DAYS = (
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            "Sunday",
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            "Monday",
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            "Tuesday",
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            "Wednesday",
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            "Thursday",
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            "Friday",
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            "Saturday",
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        )
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        difference = self.daysBetweenDates(
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            (LOWEST_DAY, LOWEST_MONTH, LOWEST_YEAR), (day, month, year)
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        )
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        return DAYS[(difference + DAY) % 7]
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    def daysBetweenDates(self, date1: tuple, date2: tuple) -> int:
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        LOWEST_YEAR = 1971
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        def daysSinceLowest(date: tuple) -> int:
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            day, month, year = date
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            isLeapYear = lambda x: (
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                1 if (x % 4 == 0 and x % 100 != 0) or x % 400 == 0 else 0
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            )
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            days: int = 0
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            # days between the LOWEST_YEAR and year
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            days += 365 * (year - LOWEST_YEAR) + sum(
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                map(isLeapYear, range(LOWEST_YEAR, year))
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            )
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            # days between year and exact date
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            daysInMonth = (
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                31,
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                28 + isLeapYear(year),
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                31,
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                30,
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                31,
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                30,
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                31,
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                31,
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                30,
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                31,
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                30,
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                31,
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            )
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            days += sum(daysInMonth[: month - 1]) + day
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            return days
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        return abs(daysSinceLowest(date1) - daysSinceLowest(date2))