1class Solution {2 public:3 vector<int> diStringMatch(string s) {4 int p = 0, j = s.size();5 vector<int> v;6 for (int i = 0; i <= s.size(); i++) {7 if (s[i] == 'I')8 v.push_back(p++);9 else10 v.push_back(j--);11 }12 return v;13 }14};
WPM •0 •0
ACC •0 •0
TIME •0