Course Schedule III LeetCode solution in JavaScript

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var scheduleCourse = function (courses) {
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  courses.sort((a, b) => a[1] - b[1]);
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  let pq = new PQ(),
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    currentDay = 0;
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  for (let [duration, lastDay] of courses) {
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    if (duration > lastDay) continue;
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    if (currentDay + duration <= lastDay) {
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      pq.offer(duration);
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      currentDay += duration;
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    } else if (duration < pq.peek() && pq.size()) {
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      currentDay += duration - pq.poll();
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      pq.offer(duration);
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    }
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  }
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  return pq.size();
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};