Count and Say LeetCode solution in Python

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class Solution:
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    def countAndSay(self, n: int) -> str:
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        if n == 1:
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            return "1"
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        x = self.countAndSay(n - 1)
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        count = 1
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        cur = x[0]
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        res = ""
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        for i in range(1, len(x)):
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            if cur == x[i]:
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                count += 1
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            else:
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                res += str(count) + str(cur)
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                count = 1
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                cur = x[i]
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        res += str(count) + str(cur)
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        return res