Count Vowel Substrings of a String LeetCode solution in Python

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class Solution:
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    def countVowelSubstrings(self, word: str) -> int:
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        vowels = {"a", "e", "i", "o", "u"}
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        pointer = 0
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        res = 0
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        if len(word) <= 4:
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            return 0
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        while pointer != len(word) - 4:
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            # if set(list(word[pointer:pointer+5])) == vowels:
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            #     temp = 1
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            #     res += 1
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            #     while set(list(word[pointer:pointer+temp+5])) == vowels and pointer+temp+4 != len(word):
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            #         res += 1
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            #         temp += 1
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            # elif word[pointer] in vowels:
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            #     temp = 1
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            #     while set(list(word[pointer:pointer+5+temp])) != vowels:
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            #         temp += 1
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            #     res += 1
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            # pointer += 1
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            temp = 0
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            if word[pointer] in vowels:
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                while temp + pointer != len(word) - 4:
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                    test_1 = set(list(word[pointer : pointer + temp + 5]))
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                    test_2 = word[pointer : pointer + temp + 5]
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                    if set(list(word[pointer : pointer + temp + 5])).issubset(vowels):
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                        if set(list(word[pointer : pointer + temp + 5])) == vowels:
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                            res += 1
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                        temp += 1
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                    else:
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                        break
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            pointer += 1
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        return res