Count Triplets That Can Form Two Arrays of Equal XOR LeetCode solution in JavaScript

1
/**
2
 * @param {number[]} arr
3
 * @return {number}
4
 */
5
var countTriplets = function (arr) {
6
  let count = 0;
7
  for (let i = 0; i < arr.length; i++) {
8
    let xor = arr[i];
9
    for (let j = i + 1; j < arr.length; j++) {
10
      xor ^= arr[j];
11
      if (xor == 0) {
12
        count += j - i;
13
      }
14
    }
15
  }
16
  return count;
17
};