Count Good Triplets LeetCode solution in JavaScript
1var countGoodTriplets = function (arr, a, b, c) {2let triplets = 0;34for (let i = 0; i < arr.length - 2; i++) {5for (let j = i + 1; j < arr.length - 1; j++) {6if (Math.abs(arr[i] - arr[j]) > a) continue;7for (let k = j + 1; k < arr.length; k++) {8if (Math.abs(arr[j] - arr[k]) > b || Math.abs(arr[i] - arr[k]) > c) {9continue;10}11triplets++;12}13}14}1516return triplets;17};