1class Solution {2 public int concatenatedBinary(int n) {3 long res = 0;4 for (int i = 1; i <= n; i++) {5 res = (res * (int) Math.pow(2, Integer.toBinaryString(i).length()) + i) % 1000000007;6 }7 return (int) res;8 }9}
WPM •0 •0
ACC •0 •0
TIME •0