Compare Version Numbers LeetCode solution in JavaScript

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var compareVersion = function (version1, version2) {
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  const v1 = version1.split(".");
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  const v2 = version2.split(".");
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  let max = Math.max(v1.length, v2.length);
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  for (let i = 0; i < max; i++) {
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    if (v1[i] && v2[i]) {
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      // if both v1 and v2 are present
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      if (+v1[i] > +v2[i]) return 1;
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      else if (+v1[i] < +v2[i]) return -1;
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    } else if (v1[i] && +v1[i] !== 0) {
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      // if v1 is larger than v2 but make sure those digits are not 0.
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      return 1;
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    } else if (v2[i] && +v2[i] !== 0) {
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      // if v2 is larger than v1 but make sure those digits are not 0.
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      return -1;
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    }
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  }
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  return 0;
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};