Compare Version Numbers LeetCode solution in Java

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class Solution {
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  public int compareVersion(String version1, String version2) {
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    // Here we are going to Split the numbers by  . but since we cannot do that in java we will
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    // replace . with # and then do it
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    version1 = version1.replace('.', '#');
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    version2 = version2.replace('.', '#');
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    String v1[] = version1.split("#");
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    String v2[] = version2.split("#");
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    int i = 0;
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    while (i < v1.length || i < v2.length) {
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      // we will have inital value  0 as our array can out out index so taking that in
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      // considerration
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      Integer i1 = 0;
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      Integer i2 = 0;
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      // Here we are using removeing Zero function which will remove all the zeros before the string
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      if (i < v1.length) {
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        i1 = Integer.valueOf(removezero(v1[i]));
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      }
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      if (i < v2.length) {
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        i2 = Integer.valueOf(removezero(v2[i]));
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      }
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      // and the rest is just the comparison
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      if (i1 < i2) {
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        return -1;
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      } else if (i1 > i2) {
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        return 1;
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      }
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      i++;
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    }
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    // if all the statments are false then at last we can say that they are equal
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    return 0;
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  }
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  String removezero(String s) {
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    String result = "";
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    int i = 0;
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    while (i < s.length()) {
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      if (s.charAt(i) != '0') {
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        result = s.substring(i, s.length());
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        break;
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      }
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      i++;
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    }
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    return result != "" ? result : "0";
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  }
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}