Compare Strings by Frequency of the Smallest Character LeetCode solution in JavaScript

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var numSmallerByFrequency = function (queries, words) {
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  const wordsF = words.map((word) => f(word));
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  return queries
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    .map((str) => f(str))
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    .map((strF) =>
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      wordsF.reduce((count, wordF) => (strF < wordF ? count + 1 : count), 0)
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    );
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};
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function f(str) {
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  return str
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    .split("")
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    .sort()
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    .reduce((sum, curr, i, arr) => (curr === arr[0] ? sum + 1 : sum), 0);
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}