Check if Number Has Equal Digit Count and Digit Value LeetCode solution in C++

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class Solution {
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 public:
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  bool digitCount(string num) {
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    unordered_map<int, int> mpp;
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    int n = num.length();
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    for (auto it : num) {
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      int x = it - '0';
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      mpp[x]++; // Store the frequency of the char as a number
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    }
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    for (int i = 0; i < n; i++) {
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      int x = num[i] - '0'; // get the char as number
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      if (mpp[i] != x) // f the number is not equal to its frequency we return false
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        return false;
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    }
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    return true;
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  }
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};