Bulls and Cows LeetCode solution in Python

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class Solution:
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    def getHint(self, secret: str, guess: str) -> str:
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        # Setup counts for bulls and cows
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        bulls = cows = 0
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        # Copy secret and guess into lists that are easier to work with
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        secretCopy = list(secret)
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        guessCopy = list(guess)
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        # In a for loop, check every pair of letters at the same index in both guess and secret for matching letters, AKA bulls
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        for i in range(len(secret)):
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            # If they match, bulls += 1 and pop() the letters from the copy lists via their .index()
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            if secret[i] == guess[i]:
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                bulls += 1
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                secretCopy.pop(secretCopy.index(secret[i]))
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                guessCopy.pop(guessCopy.index(guess[i]))
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        # Count() the letters remaining in secret and guess lists
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        secretCounter = Counter(secretCopy)
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        guessCounter = Counter(guessCopy)
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        # Counter1 - Counter2 gives us Counter1 with any matching values of Counter1 and Counter2 removed; leftover Counter2 values are trashed
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        # secretCounter - guessCounter gives us the secretCounter except for any correctly guessed letters
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        # Therefore, subtract this difference from the OG secretCounter to be left with a counter of only correctly guessed letters
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        dif = secretCounter - (secretCounter - guessCounter)
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        # The .total() of the dif Counter is the number of cows
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        cows = dif.total()
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        # return the formatted string with req. info
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        return f"{bulls}A{cows}B"