Build an Array With Stack Operations LeetCode solution in Python

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class Solution:
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    def buildArray(self, target: List[int], n: int) -> List[str]:
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        temp = []
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        result = []
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        x = target[-1]
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        for i in range(1, x + 1):
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            temp.append(i)
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        for i in range(len(temp)):
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            if temp[i] in target:
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                result.append("Push")
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            elif temp[i] not in target:
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                result.append("Push")
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                result.append("Pop")
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        return result