Build an Array With Stack Operations LeetCode solution in JavaScript
1/**2* @param {number[]} target3* @param {number} n4* @return {string[]}5*/6var buildArray = function (target, n) {7let arr = [];8let index = 0;9for (let i = 1; i <= target[target.length - 1]; i++) {10if (target[index] == i) {11arr.push("Push");12index++;13} else {14arr.push("Push");15arr.push("Pop");16}17}18return arr;19};