Build an Array With Stack Operations LeetCode solution in C++

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class Solution {
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 public:
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  vector<string> buildArray(vector<int> &target, int n) {
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    vector<string> ans;
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    int l = target.size(), count = 0,
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        ind = 0; // ind is index of the target array
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    for (int i = 1; i <= n; i++) {
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      if (count == l) break;
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      if (target[ind] != i) {
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        ans.push_back("Push");
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        ans.push_back("Pop");
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      } else {
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        ans.push_back("Push");
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        count++;
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        ind++;
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      }
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    }
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    return ans;
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  }
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};