Break a Palindrome LeetCode solution in C++

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class Solution {
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 public:
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  string breakPalindrome(string palindrome) {
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    int n = palindrome.size();
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    string res = "";
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    if (n == 1) {
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      return res;
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    }
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    int i = 0;
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    while (i < n) {
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      if (n % 2 != 0 && i == n / 2) {
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        i++;
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        continue;
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      }
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      if (palindrome[i] != 'a') {
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        palindrome[i] = 'a';
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        break;
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      }
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      i++;
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    }
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    if (i == n) {
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      palindrome[i - 1] = 'b';
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    }
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    return palindrome;
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  }
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};