Binary Prefix Divisible By 5 LeetCode solution in Java
1class Solution {2public List<Boolean> prefixesDivBy5(int[] nums) {3List<Boolean> list = new ArrayList<>();4int sum = 0;5for (int i = 0; i < nums.length; i++) {6sum = (sum * 2 + nums[i]) % 5;7if (sum == 0) list.add(true);8else list.add(false);9}10return list;11}12}