Binary Number with Alternating Bits LeetCode solution in Python

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class Solution:
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    def hasAlternatingBits(self, n: int) -> bool:
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        bin_n = bin(n)[2:]
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        for i in range(len(bin_n) - 1):
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            if bin_n[i] == "0" and bin_n[i + 1] == "0":
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                return False
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            if bin_n[i] == "1" and bin_n[i + 1] == "1":
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                return False
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        return True