Binary Number with Alternating Bits LeetCode solution in JavaScript

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/**
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 * @param {number} n
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 * @return {boolean}
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 */
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var hasAlternatingBits = function (n) {
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  let previous;
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  while (n) {
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    const current = n & 1;
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    if (previous === current) return false;
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    previous = current;
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    n >>>= 1;
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  }
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  return true;
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};