Best Time to Buy and Sell Stock II LeetCode solution in JavaScript

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/**
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 * @param {number[]} prices
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 * @return {number}
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 */
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var maxProfit = function (prices) {
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  let lowestNum = prices[0];
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  let highestNum = prices[0];
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  let profit = highestNum - lowestNum;
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  for (var indexI = 1; indexI < prices.length; indexI++) {
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    if (prices[indexI] < prices[indexI - 1]) {
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      lowestNum = prices[indexI];
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    }
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    if (prices[indexI] > lowestNum) {
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      lowestNum = prices[indexI - 1];
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      profit = profit + prices[indexI] - lowestNum;
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      highestNum = prices[indexI];
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    }
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  }
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  return profit;
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};