Backspace String Compare LeetCode solution in Python

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class Solution:
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    def backspaceCompare(self, s: str, t: str) -> bool:
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        def backwardResult(string):
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            debt = 0
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            for c in reversed(string):
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                if c == "#":
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                    debt += 1
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                elif debt > 0:
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                    debt -= 1
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                else:
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                    yield c
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        return all(
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            a == b for (a, b) in zip_longest(backwardResult(s), backwardResult(t))
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        )